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Buffalo Bills free agent WR Deonte Thompson signs with Dallas Cowboys

The Cowboys are getting a pretty good one in Thompson.

Buffalo Bills v New England Patriots Photo by Tim Bradbury/Getty Images

Another blow has been served the to the Buffalo Bills receiving corps. The team’s unrestricted free agent wide receiver Deonte Thompson has signed a contract with the Dallas Cowboys.

Thompson’s agent, David Canter, shared with NFL Network’s Ian Rapoport that the deal is for one year and worth $2.5 million with a $1 million signing bonus. The Bills reportedly met with Thompson in hopes of re-signing him.

Thompson, a veteran of seven seasons, played in 11 games with the Bills last season after being cut by the Chicago Bears in Week 6. After announcing his arrival in Buffalo in style with a 107-yard debut performance, Thompson quickly showed that he was someone that the team could depend on. He finished 2017 with more yards than any other Bills wide receiver and made several clutch plays down the stretch of season to help the Bills end their 17-year playoff drought.

His absence will definitely be felt by the Bills. Their receivers recorded the second-lowest receiving yardage total in the league a season ago. So far, the team has been unable to sign any free agents at the position.

Aside from Thompson, the Bills could also potentially lose fellow UFA wide receiver Jordan Matthews. He along with Allen Hurns, Jeremy Maclin, and Eric Decker are among the more recognizable wide receivers that remain on the market now closing in on two weeks into the free agency period.

*Update: Hurns has informed ESPN’s Josina Anderson that he’s signing with the Cowboys.