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Buffalo Bills’ Tre’Davious White awarded AFC Defensive Player of the Week

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Big yay for the big day by Big Play Tre.

The NFL has announced that Tre’Davious White was named the AFC Defensive Player of the Week, following his big day against the Miami Dolphins. White had an interception and a forced fumble, catalyzing two turnovers that led to 14 points for his team. He also had five tackles on the day.

This is the first time White was named Defensive Player of the Week. The last time a member of the Buffalo Bills earned the honor was Matt Milano in Week 3 of the previous season. (Arguably, Jordan Phillips should’ve won the award two weeks ago. His three-sack performance led the NFL that week, no one turned in a multi-interception day, and the actual winner, Justin Houston, was probably picked more for the narrative of upsetting his old team than the one-sack, four-tackle day he had against the Kansas City Chiefs.)

So far this season, White is tied for second in the NFL with three interceptions. New England’s Devin McCourty has the lead, with five in seven games. White has two forced fumbles, which leads the Bills. Along with that, he has 26 tackles (23 solo).