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AFC Playoff Picture: New York Jets officially eliminated from AFC East race

With their loss on Monday night, the New York Jets have been officially eliminated from the AFC East race after just nine games. Ouch.

The 7-2 Buffalo Bills currently sit in first place in the division while the Jets are obviously in last place at 0-9. If the Jets win out to get to 7-9 and the Bills lost out to get to 7-9, it would head to tiebreakers. Buffalo owns the head-to-head tiebreaker having already defeated the Jets twice.

If it went to a three-way tiebreaker, the first tiebreaker is head-to-head games among the three teams. At worst, Buffalo would be 3-1 in these games having already defeated the Jets twice and the New England Patriots and Miami Dolphins once. With losses to Miami and New England, the best the Jets could get to would be 1-3 in this tiebreaker scenario.

The same thing would happen in a four-way tiebreaker scenario.

The threshold for the seventh and final Wild Card spot is 5-3 right now, so the Jets are multiple games behind in that race, as well.

Miami is at 5-3, 1.5 games behind the Bills and Buffalo owns the head-to-head tiebreaker for now. New England is at 3-5, which is still alive but just barely.